Approximation Test-1 (Rounding off to Integers)

Answer: Option E

Explanation

Given,

$\frac{323}{55}\times \frac{971}{251}\times \frac{56}{61}=?$

It can be approximated as

$=\frac{330}{55}\times \frac{1000}{250}\times \frac{60}{60}=?$

= 6×4×1

=24 ≈ 21

Hence, Option E is correct.

Answer: Option A

Explanation

Given,

1002÷49×99-1299=?

It can be approximated as

1000÷50×100-1300=?

= 20×100-1300

= 2000-1300

= 700

Hence, Option A is correct.

Answer: Option E

Explanation

Given,

$\sqrt{\text{2498}}\times \sqrt{\text{626}}÷\sqrt{\text{99}}\text{ = ?}$

It can be approximated as

$\sqrt{\text{2500}}\times \sqrt{\text{625}}÷\sqrt{100}\text{ = ?}$

= 50×25÷10

= 50×2.5

= 125

$\left[\because \sqrt{2500}=50, \sqrt{625}=25\right]$

Hence, Option E is correct.

Answer: Option D

Explanation

Given,

$\sqrt{\text{769}}_3\times \sqrt{\text{478}}\text{ =?}$

It can be approximated as

$\sqrt{\text{769}}_3\times \sqrt{\text{478}}\text{ =?}$

= 9×22

= 198 ≈ 200

$\left[\because \sqrt{729}=9, \sqrt{484}=22\right]$

[ here we decrease the value of 769 to 729]

Hence, Option D is correct.

Answer: Option A

Explanation

Given,

496÷0.6×0.5=?

It can be approximated as

$$\begin{gathered} =\frac{4960}{6}\times 0.5 \\ =\frac{4960}{6}\times \frac{1}{2} \\ =826.66\times \frac{1}{2} \\ =826\times \frac{1}{2}=413 \end{gathered}$$

Hence, Option A is correct.