Approximation Test-2 (Rounding off to Integers)

Answer: Option B

Explanation

Given,

(4438-2874-559)÷(269-106-83)=?

It can be approximated as

(4400-2800-600)÷(300-100-100)=?

= (4400-3400)÷(300-200)=?

= (4400-3400)÷(300-200)

= (1000÷100)=?

= 10 ≈ 13

Hence, option B is correct.

Answer: Option E

Explanation

Given,

52001÷61×29=?×41

It can be approximated as

52000÷60×29=?×41

= 866.66×29=?=41

= 860×29 = ?×41

$=\frac{860\times 30}{40}$

= 43×15

= 645 ≈ 680

Hence, option E is correct.

Answer: Option D

Explanation

Given,

$\sqrt{\text{5378}}\times \sqrt{\text{3330}}÷\sqrt{\text{360}}\text{ =?}$

It can be approximated as 

$\sqrt{\text{5400}}\times \sqrt{\text{3300}}÷\sqrt{\text{400}}\text{ =?}$

= 72×60÷20

= 72×3

= 216 ≈ 225

Hence, Option D is correct.

Answer: Option C

Explanation

Given,

$\frac{701}{52}÷\frac{11}{699}\times \frac{112}{107}=?$

It can be approximated as

 $$\begin{gathered} = \frac{700}{49}÷\frac{10}{700}\times \frac{110}{110}=? \\ = \frac{700}{49}\times \frac{700}{10}\times \frac{110}{110}=? \\ =\frac{100}{7}\times 70 \end{gathered}$$

  = 100×10

  = 1000 ≈ 900

Hence, Option C is correct.

Answer: Option C

Explanation

Given,

(98×198)÷(48×148)=?

It can be approximated ass

(100×200)÷(50×150)=?

= 20000÷7500

= 2.73

Hence, Option C is correct.