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'A' is thrice as good a workman as 'B' and so takes 60 days less than 'B' for doing a job. The time in which they can do the job together is
[LIC (AIO), 2012]
None of the above
Let A can complete the work in x days and B in 3x days.
⇒ x=30 days
A can finish the work in 30 days and B can finish the same work in 90 days.
∴ in 1 day (A+B) can complete.130+190=490th of the work
∴(A+B) can finish the complete work in=904 or 2212 days
Hence option C is the correct
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Work and Time
'A' can do a certain job in 12 days. 'B' is 60% more efficient than 'A'. To do the same job 'B' alone would take
None of these
According to the question,
Time taken by B =100100±x x total days taken by A
=100160×12=152 or 712 days
Hence option A is the correct
'A' takes twice as much as 'B' and thrice as much as 'C' to complete a piece of work. They together complete the work in 1 day. In what time will 'A' alone complete the work?
Time taken to complete the work by
Time taken to by Ais 3x
So, 3×2=6 days
'X' is 3 times as fast as 'Y' and is able to complete the work in 40 days less than 'Y'. Then, the time in which they can complete the work together, is
We shall use the formula, klk2-1
[Here, k= number of times, l=given days]
Given, k=3, l=40
16 men and 12 women together can complete a work in 8 days. 20 men can complete the same work in 16 days. How many days will 16 women take to complete the same work?
[IBPS RRB (Scale 1), 2014]
16 men and 12 women together can complete a work in 8 days and 20 men can complete the same work in 16 days
So, (16 men+12 women)×8 days=20 men×16 days
⇒ 16 men+12 women=40 men
⇒ 12 women=(40-16)=24 men
∴ 1 woman = 2 men ...(1)
⇒ 16 women =32 men ...(2)
Now, 20 men can complete the work 16 day's
So, 32 men can complete the same work in 16×2032days=10 days
as 1 woman = 2 men
16 women can complete the same work in 10 days
Hence option E is the correct
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