Practice Test Discussion

$1 \frac{1}{3} + 2 \frac{1}{6} - 3 \frac{1}{9} = 1 \div ?$

[RBI, 2015]

$2 \frac{4}{7}$

$5 \frac{2}{7}$

$2 \frac{1}{3}$

$3 \frac{1}{3}$

$3 \frac{1}{7}$

Explanation

In this question,

$\Rightarrow 1 \frac{1}{3} + 2 \frac{1}{6} - 3 \frac{1}{9} = 1 \div x \Rightarrow \frac{4}{3} + \frac{13}{6} - \frac{28}{9} = 1 \div x \Rightarrow \frac{24 + 39 - 56}{18} = 1 \div x \Rightarrow \frac{7}{18} = 1 \div x \Rightarrow x = \frac{18}{7} = 2 \frac{4}{7}$

Hence, Option A is correct.

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