In this above question,

We add fractional and integral part separately.

$$\begin{gathered} =1+\frac{1}{4}+1+\frac{1}{6}-\left(1+\frac{1}{8}\right)=?+1+\frac{1}{12} \\ = (1+1-1-1)+\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{8}-\frac{1}{12}\right)=? \\ = ? =0+\frac{6+4-3-2}{24} \\ = ? =\frac{5}{24} \end{gathered}$$

Hence, Option A is correct.