$\begin{array}{l}\text{Here, }\\ \Rightarrow \text{348}÷\text{29}\times {\text{15 + 156 = (?)}}^{\text{3}}\text{+120}\\ \\ \text{Applying the BODMAS rule, we get}\\ \\ \Rightarrow \text{12}\times {\text{15 + 156 = (?)}}^{\text{3}}\text{+120}\\ \\ \Rightarrow \text{ 336}-{\text{120 = (?)}}^{\text{3}}\\ \\ \Rightarrow {\text{(?)}}^{\text{3}}\text{ = 216}\\ \\ \Rightarrow \text{? =}\sqrt{\text{216}}_3=6\end{array}$

Hence, Option B is correct.