According to the above given formula, If M₁ persons can do W₁ work in D₁ days working T₁ hours a day and M₂ persons can do W₂ work in D₂ days working T₂ hours a day then,

M₁D₁W₁= M₂D₂W₂

Here W₁=W₂

$$\begin{gathered} 16\times 10\times 1= 8\times {\mathrm{M}}_2\times 1 \\ {\mathrm{M}}_2=\frac{16\times 10 \times 1}{8 \times 1} =\frac{160}{8}=20 \end{gathered}$$

Hence, 20 men can complete the same work in 8 days

Hence option C is correct