$$\begin{gathered} \begin{array}{l}\text{Here,}\\ \Rightarrow \frac{1}{6}of\left(92\right)\%of1\frac{1}{23}of\left(650\right)=85+?\\ \\ \Rightarrow \frac{1}{6}\times \frac{92}{100}\times \frac{24}{23}\times 650=85+?\\ \end{array} \\ Reduce the numbers with greatest common divisor 23 and 6 \\ =\frac{4}{100}\times 4\times 650=85+? \\ Reduce the numbers with greatest common divisor 50 \\ =\frac{4}{2}\times 4\times 13=85+? \\ =2\times 4\times 13=85+? \\ =104=85+? \\ =-?=85-104 \\ =-?=-19 \\ =?=19 \end{gathered}$$

Hence, Option C is correct.