$\begin{array}{l}\text{Here, }\\ \text{Given expression is}\\ \frac{{\text{(1111)}}^{\text{3}}{\text{+ (2212)}}^{\text{3}}-{\text{(3.323)}}^{\text{3}}}{\text{(1.111)(2212)(- 3.323)}}\\ \\ \text{Here, put a= 1.111, b = 2.112}\\ \text{and c = 3.323}\\ \\ \text{So, given expression can also be }\\ \text{written as}\\ \\ \Rightarrow \frac{{\text{a}}^{\text{3}}{\text{+ b}}^{\text{3}}{\text{+(-c)}}^{\text{3}}}{-abc}\\ \\ \text{Now, here, a + b + c = 0}\\ \\ {\text{Hence, a}}^{\text{3}}{\text{+ b}}^{\text{3}}{\text{+ c}}^{\text{3}}\text{= 3abc}\\ \\ \text{So,\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\frac{3abc}{abc}=3\\ \\ \text{So, its value lies between 2.5 and 3.5.}\end{array}$

Hence, option E is correct.