According to the above given formula, If M₁ persons can do W₁ work in D₁ days working T₁ hours a day and M₂ persons can do W₂ work in D₂ days working T₂ hours a day then, M₁T₁W₁= M₂T₁W₂

Here, M₁=6, T₁=16  M₂=8 T₂=?  and W₁=W₂=1

$$\begin{gathered} 6\times 16\times 1= 8\times {\mathrm{T}}_2\times 1 \\ {\mathrm{T}}_2=\frac{6\times 16\times 1}{8\times 1} =12 \mathrm{hours} \end{gathered}$$

Hence, 8 boys will complete the same work in 12 hours

Hence option C is correct