Practice Test Discussion

On a school's annual Day, sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus, the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get?

Cannot be determined

None of these

Explanation

$\begin{array}{l} Let the total number of sweets be x \\ According to the question, \\ \frac{x}{112 - 32} - \frac{x}{112} = 6 \\ \Rightarrow \frac{x}{80} - \frac{x}{112} = 6 \\ \Rightarrow \frac{7 x - 5 x}{560} = 6 \\ \Rightarrow \frac{2 x}{560} = 6 \\ \Rightarrow x = \frac{560 \times 6}{2} = 1680 \\ ∴ Required answer = \frac{1680}{112} = 15 \end{array}$

Hence, option D is correct.

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