Ten years ago, the average age of a family of 4 members was 24 years. Two children having been born, the average age of the family is same today. find the present age of the youngest child, assuming that the children age differ by 2 years?
Explanation
Given,
The average age of a family 4 members was 24 yrs
= 24×4= 96 yrs
Total age of 4 members, 10 years ago
= [96+(10×4)]
= 136 yrs
Two children are born (4 members +2 child)
= 6×24=144 yrs
Sum of the ages two children
= 144-136= 8
Let the age of younger child be 'x' years
The age of the elder child =(x+2) years
∴ The present age of the youngest child
= x(x+2)=8
= 2x+2=8
= 2x=6
= x= 3
Hence, Option B is correct.
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