Practice Test Discussion

90 men are engaged to do a piece of work in 40 days, but it was found that in 25 days, two-third of the work is completed. How many men should be allowed to go off so that the work may be finshed on time?

[SSC 2008]

10 men

15 men

20 men

25 men

None of these

Explanation

Here,

M₁ = 90, D₁ =25, W₂ = $1 - \frac{2}{3}$

M₂ = 90-x, D₂ = 15, W₁= $\frac{2}{3}$

So according to the formula,

M₁ D₁ W₂ = M₂ D₂ W₁

_{$(90 \times 25) [1 - \frac{2}{3}] = (90 - x) \times 15 \times \frac{2}{3} 90 \times 25 \times \frac{1}{3} = 10 (90 - x) 75 = 90 - X x = 90 - 75 = 15 m e n$}

Hence option B is correct

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