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Q)

A and B can do a piece of work in 60 days and 75 days, respectively. Both begin together but after a certain time 'A' leaves off. In such case 'B' finishes the remaining work in 30 days. After how many days did 'A' leave?

Explanation

Given that,

a=60 days, b=75 days, x=30, T=?

According to the formula,

$=\frac{(b+x)a}{a+b}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=\frac{(75-30)\times 60}{60+75}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=\frac{45\times 60}{135}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=20days$

**Hence option C is the correct **

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