Simplification for IBPS PO test 4-Solved questions with detailed explanations for SSC, IBPS PO, SBI PO, RRB, RBI, CSE, CGL, CHSL, CDA, CSE, UPSC

1)

What will come in place of question mark (?) in the following questions

$3 \frac{3}{4} + 4 \frac{2}{5} - 3 \frac{1}{8} = ?$

[BOB (PO), 2010]

A)
$4 \frac{1}{40}$
B)
$5 \frac{1}{40}$
C)
$6 \frac{1}{40}$
D)
$5 \frac{3}{40}$
E)
None of these

Answer: Option B

Explanation

In this above question,

we add the integral part and fractional part separately.

$= ? = 3 + \frac{3}{4} + 4 + \frac{2}{5} - (3 + \frac{1}{8}) = ? = (3 + 4 - 3) + (\frac{3}{4} + \frac{2}{5} - \frac{1}{8}) = ? = 4 + (\frac{30 + 16 - 5}{40}) = \frac{160 + 41}{40} = 5 \frac{1}{40}$

Hence, Option B is correct.

Discussion

2)

$5 \frac{17}{37} \times 4 \frac{51}{52} \times 11 \frac{1}{7} + 2 \frac{3}{4} = ?$

[Punjab and Sindh Bank (PO), 2009]

A)
303.75
B)
305.75
C)
$303 \frac{3}{4}$
D)
$305 \frac{1}{4}$
E)
None of these

Answer: Option B

Explanation

Here,

$= 5 \frac{17}{37} \times 4 \frac{51}{52} \times 11 \frac{1}{7} + 2 \frac{3}{4} = \frac{202}{37} \times \frac{259}{52} \times \frac{78}{7} + \frac{11}{4}$

We follow the order of BODMAS

$= ? = \frac{202 \times 7}{52} \times \frac{78}{7} + \frac{11}{4} = ? = \frac{101 \times 6}{2} + \frac{11}{4} = ? = \frac{1212 + 11}{4} = \frac{1223}{4} = 305.75$

Hence, Option B is correct.

Discussion

3)

$\frac{3}{8} o f \frac{4}{5} o f \frac{2}{3} o f 730 = ?$

[Andhra Bank (PO), 2009]

A)
86
B)
146
C)
156
D)
93
E)
None of these

Answer: Option B

Explanation

Here,

$= \frac{3}{8} \times \frac{4}{5} \times \frac{2}{3} \times 730 = \frac{24}{120} \times 730 = 146$

Hence, Option B is correct.

Discussion

4)

$1 \frac{1}{4} + 1 \frac{5}{9} \times 1 \frac{5}{8} \div 6 \frac{1}{2} = ?$

[Corporation Bank (PO), 2009]

A)
17
B)
27
C)
42
D)
18
E)
None of these

Answer: Option E

Explanation

Here,

We follow the order of BODMAS

$= \frac{5}{4} + \frac{14}{9} \times \frac{13}{8} \div \frac{13}{2} = ? = ? = \frac{5}{4} + \frac{14}{9} \times \frac{13}{8} \times \frac{2}{13} = \frac{5}{4} + \frac{7}{18} = \frac{45 + 14}{36} = \frac{59}{36}$

Hence, Option E is correct

Discussion

5)

$3 \frac{2}{7} - 2 \frac{1}{14} - 1 \frac{1}{7} = ? + 2 \frac{1}{13}$

[Andhra Bank (PO), 2009]

A)
$1 \frac{1}{7}$
B)
$1 \frac{2}{7}$
C)
$\frac{1}{7}$
D)
$\frac{3}{7}$
E)
None of these

Answer: Option E

Explanation

Here,

$3 \frac{2}{7} - 2 \frac{1}{14} - 1 \frac{1}{14} - 1 \frac{1}{7} - 2 \frac{1}{13} = ?$

Now, solve the integral part and fractional part separately

$= 3 \frac{2}{7} - (2 \frac{1}{14} + 1 \frac{1}{14} + 1 \frac{1}{7} + 2 \frac{1}{13}) = ?$

By adding integral part we get (2+1+1+2)=6

$= \frac{23}{7} - \{(6) + (\frac{1}{14} + \frac{1}{14} + \frac{1}{7} + \frac{1}{3})\} = ? = 3 \frac{2}{7} - \{(6) + (\frac{1}{7} + \frac{1}{7} + \frac{1}{13})\} = ? = \frac{23}{7} - \{6 + \frac{26 + 7}{91}\} = ? = ? = \frac{299 - 579}{91} = \frac{- 289}{91}$

Hence, Option E is correct.

Discussion

Simplification-Test 4 (Based on Fractions/Square roots and Cube roots)

Answer: Option B

Answer: Option B

Answer: Option B

Answer: Option E

Answer: Option E