Simplification for IBPS PO test 4-Solved questions with detailed explanations for SSC, IBPS PO, SBI PO, RRB, RBI, CSE, CGL, CHSL, CDA, CSE, UPSC

21)

What will come in place of question mark (?) in the following questions

$68 \times \sqrt{?} - 3421 = 591$

[Bank of India (PO), 2010]

A)
3249
B)
3481
C)
3364
D)
3136
E)
None of these

Answer: Option B

Explanation

$\begin{array}{l} Here, \\ \Rightarrow 68 \times \sqrt{?} = 591 + 3421 = 4012 \\ \Rightarrow \sqrt{?} = \frac{4012}{68} = 59 \\ \Rightarrow ? = 59 \times 59 = 3481 \end{array}$

Hence, Option B is correct.

Discussion

22)

$\frac{343 \times 49}{216 \times 16 \times 81} = ?$

[Bank of Baroda (PO), 2010]

A)
$\frac{7^{5}}{6^{7}}$
B)
$\frac{7^{5}}{6^{8}}$
C)
$\frac{7^{6}}{6^{7}}$
D)
$\frac{7^{4}}{6^{8}}$
E)
$\frac{7^{5}}{6^{7}}$

Answer: Option A

Explanation

$\begin{array}{l} Here, \\ \Rightarrow \frac{7^{3} \times 7^{2}}{6^{3} \times 4^{2} \times 9^{2}} \\ [\begin{array}{l} ∵ 343 = 7^{3}, 49 = 7^{2} \\ 216 = 6^{3}, 16 = 4^{2}, 81 = 9^{2} \end{array}] \\ \Rightarrow \frac{7^{5}}{6^{3} \times {(4 \times 9)}^{2}} = \frac{7^{5}}{6^{3} \times {(6)}^{4}} \\ = \frac{7^{5}}{6^{3} \times 6^{4}} = \frac{7^{5}}{6^{7}} \end{array}$

Hence Option A is correct.

Discussion

23)

${(35)}^{2} \div {}^{3}{\sqrt{125}} {+ (25)}^{2} \div 125 =?$

[Bank of Maharashtra (PO), 2009]

A)
200
B)
250
C)
50
D)
100
E)
None of these

Answer: Option B

Explanation

$\begin{array}{l} Here, \\ \Rightarrow {(35)}^{2} \div {}^{3}{\sqrt{125}} {+ (25)}^{2} +125 =? \\ \Rightarrow 1225 \div 5 + 625 \div 125 =? \\ Applying the BODMAS rule to solve the \\ expression, we get \\ \Rightarrow 1225 \div 5+ 5=? \\ \Rightarrow 245 + 5 = ? \Rightarrow ? = 250 \end{array}$

Hence, Option B is correct.

Discussion

24)

${(?)}^{3} = 4913$

[Bank of Maharashtra (PO), 2009]

A)
27
B)
19
C)
17
D)
29
E)
None of these

Answer: Option C

Explanation

$\begin{array}{l} Here, \\ \Rightarrow {(?)}^{3} = 4913 \\ \Rightarrow ? = {}^{3}{\sqrt{4913}} = 17 \end{array}$

Hence, Option C is correct.

Discussion

25)

$1802 \div 34 \div 5 = \sqrt{?}$

[Bank of Baroda (PO), 2009]

A)
10.6
B)
114.49
C)
11.4
D)
110.25
E)
None of these

Answer: Option E

Explanation

$\begin{array}{l} Here, \sqrt{?} = 1802 \div 34 \div 5 \\ By applying BODMAS rule, we get \\ \Rightarrow \sqrt{?} = 1802 \times \frac{1}{34} \times \frac{1}{5} = 10.6 \\ \Rightarrow ? = 10 .6 \times \frac{1}{34} \times \frac{1}{5} = 10 .6 \\ \Rightarrow ? = 10 .6 \times 10 .6 = 112 .36 \end{array}$

Hence, Option E is correct.

Discussion

Simplification-Test 4 (Based on Fractions/Square roots and Cube roots)

Answer: Option B

Answer: Option A

Answer: Option B

Answer: Option C

Answer: Option E