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A and B together can complete a work in 3 days. They started together but after 2 days, B left the work. If the work is completed after 2 more days, B alone could do the work in how many days?
None of these
According to the question,
A+B can complete a work in 3 days.
In 2 days,
(A+B) can complete⇒ 2×13=23 of the work
A alone in complete⇒ 1-23=13of the work
B alone can complete⇒ 23-13=13of the work
So in 1 day B can complete⇒16 of the work. Therefore, B alone will take 6 days to complete the work.
Hence option B is correct
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Work and Time
90 men are engaged to do a piece of work in 40 days, but it was found that in 25 days, two-third of the work is completed. How many men should be allowed to go off so that the work may be finshed on time?
M1 = 90, D1 =25, W2 =1-23
M2 = 90-x, D2 = 15, W1 = 23
So according to the formula,
M1 D1 W2 = M2 D2 W1
90×25 1-23=90-x ×15×2390×25×13=1090-x75=90-Xx=90-75=15 men
36 work men are employed to finish a certain work in 48 days. But it is found that in 24 days only 25 work is done. How many more men must be taken to finish the work in time.
[LIC ADO 2007]
M1 = 36, D1 =24, W2 =1-25
M2 = 36+x, D2 = 24, W1 = 23
36×24 1-25=36+x×24×2536×24×35=36+x×24×2536×3=236+x108=72+2xx=362=18 men
Hence option A is correct
If 12 men or 18 women can do a piece of work in 14 days. How long will 8 men and 16 women take to finish the work?
As per the question,
12 men = 18 women
So 1 man = 1812 women
⇒ 8 men = 1812×8=12 women
M1 = 18, D1 =14, W2 =1
M2 = 12+16, D2 = ?, W1 = 1
18×14×1=12+16×D2×1 D2=18×1428=9 days
20 men complete one-third of a project in 20 days. How many more men should be employed to finish the rest of project in 25 more days?
M1 = 20, D1 =20, W2 =1-13
M2 = 20+x, D2 = 25, W1 = 13
Hence option C is correct
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