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Q)

Two pipes A and B can fill a tank in 12 and 16 min respectively. If both the pipes are opened together, then calculate the time after which B should be closed, so that the tank is full in 9 minutes.

Explanation

According to the formula, If Two pipes A and B can fill the tank in x and y min respectively. If both pipes are opened together, then the time after which pipe B should be closed so that the tank is full in t min is $\left\{\mathrm{y}\left[1-\frac{\mathrm{t}}{\mathrm{x}}\right]\right\}$ min.

So, $\left\{16\left[1-\frac{9}{12}\right]\right\}{=}{16}{\times}\frac{3}{12}{=}{4}{}{\mathrm{min}}$

The tank will be filled in 4 min both the pipes are opened simultaneously.

**Hence option A is correct**

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