A tap can empty a tank in 1 hour. A second tap can empty the tap in 30 min. If both the taps are operated simultaneously, how much time is needed to empty the tank?
[SSC CGL 2000]
Explanation
According to the above given formula, if pipe A can comletely fill a tank in x hours and pipe B can empty the same tank in y hours, then the time taken to fill the tank when both the pipes are opened simultaneously is hours.
So,
Therefore, the tank will be filled in 20 minutes when both the pipes are opened simultaneously.
Hence option A is correct.
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