Practice Test Discussion

Q)

A tap can empty a tank in 1 hour. A second tap can empty the tap in 30 min. If both the taps are operated simultaneously, how much time is needed to empty the tank?

[SSC CGL 2000]


  • Explanation

    According to the above given formula, if pipe A can comletely fill a tank in x hours and pipe B can empty the same tank in y hours, then the time taken to fill the tank when both the pipes are opened simultaneously is  xyx-y hours.

    So, 60×3060-(-30)=180090=20 minutes

    Therefore, the tank will be filled in 20 minutes when both the pipes are opened simultaneously.

    Hence option A is correct.

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