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A tank can be filled by a pipe A in 2 h and pipe B in 6 h. At 10 am pipe A was opened. At what time will the tank be filled if pipe B is opened at 11 am?
[SSC CGL 2012]
According to the question,
Pipe A fills the tank in 2 hours (in 1 hour it fills 12 part of the tank)
Pipe B fills the tank in 6 hours (in 1 hour it fills 16 part of the tank)
As pipe A was opened at 10:00 am and it worked alone till 11:00 am. In 1 hour it will fill 12 part of the tank.
the remaining 12 part of the tank will be filled by both Pipe A and B.
According to the formula, if pipe A can comletely fill a tank in x hours and pipe B can comletely fill a tank in y hours, then the time taken by both pipes together to fill the tank is xyx+y hours.
So, 2×62+6=128=32 part (both the pipes together will fill 32 part of the tank)
So, Time taken by both pipes to fill 32 part of the tank = 60 minutesTime taken to fill 12 part = 60×32×12 = 45 minutes
Therefore, the tank will be filled at 11:45 AM
Hence option C is correct.
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