As per the question,

In 1 minute,

Pipe with 2 cm diameter fills$=\frac{1}{61}$^th of the cistern

Pipe with 1 cm diameter fills$=\frac{1}{61}{\left(\frac{1}{2}\right)}^2=\frac{1}{61}\times \frac{1}{4}$^th of the cistern

Pipe with $1\frac{1}{3}$ cm diameter fills$=\frac{1}{61}\times \frac{1}{4}{\left(\frac{4}{3}\right)}^2=\frac{1}{61}\times \frac{4}{9}$^th of the cistern

∴ In 1 min all the pipes to gether can fill $\frac{1}{61}+\frac{1}{61\times 4}+\frac{4}{61\times 9}=\frac{1}{36}$

Hence in 36 Minutes the complete tank will be filled.

Hence option D is correct.